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133412443103 is a prime number
BaseRepresentation
bin111110001000000000…
…0000101001111011111
3110202100202001022112102
41330100000011033133
54141212041134403
6141142215355315
712432041025032
oct1742000051737
9422322038472
10133412443103
1151641934145
1221a33682b3b
13c771b66234
146658795019
15370c727b88
hex1f100053df

133412443103 has 2 divisors, whose sum is σ = 133412443104. Its totient is φ = 133412443102.

The previous prime is 133412443097. The next prime is 133412443163. The reversal of 133412443103 is 301344214331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133412443103 is a prime.

It is a super-2 number, since 2×1334124431032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133412443163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706221551 + 66706221552.

It is an arithmetic number, because the mean of its divisors is an integer number (66706221552).

Almost surely, 2133412443103 is an apocalyptic number.

133412443103 is a deficient number, since it is larger than the sum of its proper divisors (1).

133412443103 is an equidigital number, since it uses as much as digits as its factorization.

133412443103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 133412443103 its reverse (301344214331), we get a palindrome (434756657434).

The spelling of 133412443103 in words is "one hundred thirty-three billion, four hundred twelve million, four hundred forty-three thousand, one hundred three".