Base | Representation |
---|---|
bin | 111110001000000000… |
… | …0000101001111011111 |
3 | 110202100202001022112102 |
4 | 1330100000011033133 |
5 | 4141212041134403 |
6 | 141142215355315 |
7 | 12432041025032 |
oct | 1742000051737 |
9 | 422322038472 |
10 | 133412443103 |
11 | 51641934145 |
12 | 21a33682b3b |
13 | c771b66234 |
14 | 6658795019 |
15 | 370c727b88 |
hex | 1f100053df |
133412443103 has 2 divisors, whose sum is σ = 133412443104. Its totient is φ = 133412443102.
The previous prime is 133412443097. The next prime is 133412443163. The reversal of 133412443103 is 301344214331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133412443103 is a prime.
It is a super-2 number, since 2×1334124431032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133412443163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706221551 + 66706221552.
It is an arithmetic number, because the mean of its divisors is an integer number (66706221552).
Almost surely, 2133412443103 is an apocalyptic number.
133412443103 is a deficient number, since it is larger than the sum of its proper divisors (1).
133412443103 is an equidigital number, since it uses as much as digits as its factorization.
133412443103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 133412443103 its reverse (301344214331), we get a palindrome (434756657434).
The spelling of 133412443103 in words is "one hundred thirty-three billion, four hundred twelve million, four hundred forty-three thousand, one hundred three".
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