Base | Representation |
---|---|
bin | 10011011010100000011… |
… | …111110000001011000110 |
3 | 11201112121222202010220002 |
4 | 103122200133300023012 |
5 | 133324300412240402 |
6 | 2500520402241302 |
7 | 165250022324165 |
oct | 23324037601306 |
9 | 4645558663802 |
10 | 1334132540102 |
11 | 47489104681a |
12 | 196692356232 |
13 | 98a676a892b |
14 | 488027a93dc |
15 | 24a85755602 |
hex | 136a07f02c6 |
1334132540102 has 4 divisors (see below), whose sum is σ = 2001198810156. Its totient is φ = 667066270050.
The previous prime is 1334132540077. The next prime is 1334132540119. The reversal of 1334132540102 is 2010452314331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333533135024 + ... + 333533135027.
It is an arithmetic number, because the mean of its divisors is an integer number (500299702539).
Almost surely, 21334132540102 is an apocalyptic number.
1334132540102 is a deficient number, since it is larger than the sum of its proper divisors (667066270054).
1334132540102 is an equidigital number, since it uses as much as digits as its factorization.
1334132540102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 667066270053.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 1334132540102 its reverse (2010452314331), we get a palindrome (3344584854433).
The spelling of 1334132540102 in words is "one trillion, three hundred thirty-four billion, one hundred thirty-two million, five hundred forty thousand, one hundred two".
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