133414040401 has 2 divisors, whose sum is σ = 133414040402. Its totient is φ = 133414040400.

The previous prime is 133414040399. The next prime is 133414040411. The reversal of 133414040401 is 104040414331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116991361600 + 16422678801 = 342040^2 + 128151^2 .

It is a cyclic number.

It is not a de Polignac number, because 133414040401 - 2¹ = 133414040399 is a prime.

It is a super-2 number, since 2×133414040401² (a number of 23 digits) contains 22 as substring.

Together with 133414040399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133414040411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66707020200 + 66707020201.

It is an arithmetic number, because the mean of its divisors is an integer number (66707020201).

Almost surely, 2^133414040401 is an apocalyptic number.

It is an amenable number.

133414040401 is a deficient number, since it is larger than the sum of its proper divisors (1).

133414040401 is an equidigital number, since it uses as much as digits as its factorization.

133414040401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 133414040401 its reverse (104040414331), we get a palindrome (237454454732).

The spelling of 133414040401 in words is "one hundred thirty-three billion, four hundred fourteen million, forty thousand, four hundred one".