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133414220438 = 266707110219
BaseRepresentation
bin111110001000000011…
…0110111001010010110
3110202100212101121120122
41330100012313022112
54141213020023223
6141142321431542
712432062106542
oct1742006671226
9422325347518
10133414220438
1151642938514
1221a3419b5b2
13c772339205
146658ad8a22
15370c9795c8
hex1f101b7296

133414220438 has 4 divisors (see below), whose sum is σ = 200121330660. Its totient is φ = 66707110218.

The previous prime is 133414220413. The next prime is 133414220447. The reversal of 133414220438 is 834022414331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 834022414331 = 6917120575743.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 133414220398 and 133414220407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33353555108 + ... + 33353555111.

It is an arithmetic number, because the mean of its divisors is an integer number (50030332665).

Almost surely, 2133414220438 is an apocalyptic number.

133414220438 is a deficient number, since it is larger than the sum of its proper divisors (66707110222).

133414220438 is an equidigital number, since it uses as much as digits as its factorization.

133414220438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66707110221.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 133414220438 its reverse (834022414331), we get a palindrome (967436634769).

The spelling of 133414220438 in words is "one hundred thirty-three billion, four hundred fourteen million, two hundred twenty thousand, four hundred thirty-eight".

Divisors: 1 2 66707110219 133414220438