Base | Representation |
---|---|
bin | 111110001000000011… |
… | …0110111001010010110 |
3 | 110202100212101121120122 |
4 | 1330100012313022112 |
5 | 4141213020023223 |
6 | 141142321431542 |
7 | 12432062106542 |
oct | 1742006671226 |
9 | 422325347518 |
10 | 133414220438 |
11 | 51642938514 |
12 | 21a3419b5b2 |
13 | c772339205 |
14 | 6658ad8a22 |
15 | 370c9795c8 |
hex | 1f101b7296 |
133414220438 has 4 divisors (see below), whose sum is σ = 200121330660. Its totient is φ = 66707110218.
The previous prime is 133414220413. The next prime is 133414220447. The reversal of 133414220438 is 834022414331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 834022414331 = 6917 ⋅120575743.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 133414220398 and 133414220407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33353555108 + ... + 33353555111.
It is an arithmetic number, because the mean of its divisors is an integer number (50030332665).
Almost surely, 2133414220438 is an apocalyptic number.
133414220438 is a deficient number, since it is larger than the sum of its proper divisors (66707110222).
133414220438 is an equidigital number, since it uses as much as digits as its factorization.
133414220438 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66707110221.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 133414220438 its reverse (834022414331), we get a palindrome (967436634769).
The spelling of 133414220438 in words is "one hundred thirty-three billion, four hundred fourteen million, two hundred twenty thousand, four hundred thirty-eight".
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