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13341431203341 = 35975375317533
BaseRepresentation
bin1100001000100100101101…
…0001001000011000001101
31202020102120021112202102020
43002021023101020120031
53222041222342001331
644212545140120353
72544613050060243
oct302111321103015
952212507482366
1013341431203341
11428408411630a
1215b57aa3960b9
1375a126221957
14341a2b84a793
151820942d7c96
hexc224b44860d

13341431203341 has 8 divisors (see below), whose sum is σ = 18090076208160. Its totient is φ = 8743536833712.

The previous prime is 13341431203271. The next prime is 13341431203417. The reversal of 13341431203341 is 14330213414331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13341431203341 - 210 = 13341431202317 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13341431201341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37687658590 + ... + 37687658943.

It is an arithmetic number, because the mean of its divisors is an integer number (2261259526020).

Almost surely, 213341431203341 is an apocalyptic number.

It is an amenable number.

13341431203341 is a deficient number, since it is larger than the sum of its proper divisors (4748645004819).

13341431203341 is an equidigital number, since it uses as much as digits as its factorization.

13341431203341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75375317595.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13341431203341 its reverse (14330213414331), we get a palindrome (27671644617672).

The spelling of 13341431203341 in words is "thirteen trillion, three hundred forty-one billion, four hundred thirty-one million, two hundred three thousand, three hundred forty-one".

Divisors: 1 3 59 177 75375317533 226125952599 4447143734447 13341431203341