1334143244363 has 4 divisors (see below), whose sum is σ = 1334158818048. Its totient is φ = 1334127670680.

The previous prime is 1334143244339. The next prime is 1334143244377. The reversal of 1334143244363 is 3634423414331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1334143244363 - 2¹⁰ = 1334143243339 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1334143244363.

It is not an unprimeable number, because it can be changed into a prime (1334143244323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7657628 + ... + 7829913.

It is an arithmetic number, because the mean of its divisors is an integer number (333539704512).

Almost surely, 2^{1334143244363} is an apocalyptic number.

1334143244363 is a deficient number, since it is larger than the sum of its proper divisors (15573685).

1334143244363 is an equidigital number, since it uses as much as digits as its factorization.

1334143244363 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15573684.

The product of its digits is 746496, while the sum is 41.

Adding to 1334143244363 its reverse (3634423414331), we get a palindrome (4968566658694).

The spelling of 1334143244363 in words is "one trillion, three hundred thirty-four billion, one hundred forty-three million, two hundred forty-four thousand, three hundred sixty-three".