133414532441 has 4 divisors (see below), whose sum is σ = 141262446132. Its totient is φ = 125566618752.

The previous prime is 133414532411. The next prime is 133414532477. The reversal of 133414532441 is 144235414331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 144235414331 = 31 ⋅4652755301.

It can be written as a sum of positive squares in 2 ways, for example, as 91463300041 + 41951232400 = 302429^2 + 204820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133414532441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133414532411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3923956820 + ... + 3923956853.

It is an arithmetic number, because the mean of its divisors is an integer number (35315611533).

Almost surely, 2^133414532441 is an apocalyptic number.

It is an amenable number.

133414532441 is a deficient number, since it is larger than the sum of its proper divisors (7847913691).

133414532441 is an equidigital number, since it uses as much as digits as its factorization.

133414532441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7847913690.

The product of its digits is 69120, while the sum is 35.

Adding to 133414532441 its reverse (144235414331), we get a palindrome (277649946772).

The spelling of 133414532441 in words is "one hundred thirty-three billion, four hundred fourteen million, five hundred thirty-two thousand, four hundred forty-one".