Base | Representation |
---|---|
bin | 1100001000100101000011… |
… | …0110111100111100001001 |
3 | 1202020102210211001022210020 |
4 | 3002021100312330330021 |
5 | 3222041420400112131 |
6 | 44213002330411053 |
7 | 2544615266262543 |
oct | 302112066747411 |
9 | 52212724038706 |
10 | 13341525004041 |
11 | 4284122063153 |
12 | 15b5815890a89 |
13 | 75a13c7a4820 |
14 | 341a3a0a6693 |
15 | 18209c665996 |
hex | c2250dbcf09 |
13341525004041 has 32 divisors (see below), whose sum is σ = 20291192022528. Its totient is φ = 7724458291200.
The previous prime is 13341525004001. The next prime is 13341525004043. The reversal of 13341525004041 is 14040052514331.
It is not a de Polignac number, because 13341525004041 - 213 = 13341524995849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13341525003993 and 13341525004011.
It is not an unprimeable number, because it can be changed into a prime (13341525004043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1735041 + ... + 5449166.
It is an arithmetic number, because the mean of its divisors is an integer number (634099750704).
Almost surely, 213341525004041 is an apocalyptic number.
It is an amenable number.
13341525004041 is a deficient number, since it is larger than the sum of its proper divisors (6949667018487).
13341525004041 is a wasteful number, since it uses less digits than its factorization.
13341525004041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7187041.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 13341525004041 its reverse (14040052514331), we get a palindrome (27381577518372).
The spelling of 13341525004041 in words is "thirteen trillion, three hundred forty-one billion, five hundred twenty-five million, four thousand, forty-one".
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