Base | Representation |
---|---|
bin | 1100001000100110110110… |
… | …1000101100011100000111 |
3 | 1202020111001110112012011021 |
4 | 3002021231220230130013 |
5 | 3222043412444240303 |
6 | 44213122254452011 |
7 | 2544633251106553 |
oct | 302115550543407 |
9 | 52214043465137 |
10 | 13342007805703 |
11 | 428434a643195 |
12 | 15b592b504007 |
13 | 75a1b8817795 |
14 | 341a84262863 |
15 | 1820c9c32ebd |
hex | c226da2c707 |
13342007805703 has 2 divisors, whose sum is σ = 13342007805704. Its totient is φ = 13342007805702.
The previous prime is 13342007805697. The next prime is 13342007805761. The reversal of 13342007805703 is 30750870024331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13342007805703 - 213 = 13342007797511 is a prime.
It is a super-3 number, since 3×133420078057033 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13342007805703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13342007805103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671003902851 + 6671003902852.
It is an arithmetic number, because the mean of its divisors is an integer number (6671003902852).
Almost surely, 213342007805703 is an apocalyptic number.
13342007805703 is a deficient number, since it is larger than the sum of its proper divisors (1).
13342007805703 is an equidigital number, since it uses as much as digits as its factorization.
13342007805703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 13342007805703 in words is "thirteen trillion, three hundred forty-two billion, seven million, eight hundred five thousand, seven hundred three".
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