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13342007805703 is a prime number
BaseRepresentation
bin1100001000100110110110…
…1000101100011100000111
31202020111001110112012011021
43002021231220230130013
53222043412444240303
644213122254452011
72544633251106553
oct302115550543407
952214043465137
1013342007805703
11428434a643195
1215b592b504007
1375a1b8817795
14341a84262863
151820c9c32ebd
hexc226da2c707

13342007805703 has 2 divisors, whose sum is σ = 13342007805704. Its totient is φ = 13342007805702.

The previous prime is 13342007805697. The next prime is 13342007805761. The reversal of 13342007805703 is 30750870024331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13342007805703 - 213 = 13342007797511 is a prime.

It is a super-3 number, since 3×133420078057033 (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13342007805703.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13342007805103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671003902851 + 6671003902852.

It is an arithmetic number, because the mean of its divisors is an integer number (6671003902852).

Almost surely, 213342007805703 is an apocalyptic number.

13342007805703 is a deficient number, since it is larger than the sum of its proper divisors (1).

13342007805703 is an equidigital number, since it uses as much as digits as its factorization.

13342007805703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 423360, while the sum is 43.

The spelling of 13342007805703 in words is "thirteen trillion, three hundred forty-two billion, seven million, eight hundred five thousand, seven hundred three".