13342104002001 has 4 divisors (see below), whose sum is σ = 17789472002672. Its totient is φ = 8894736001332.

The previous prime is 13342104001991. The next prime is 13342104002011. The reversal of 13342104002001 is 10020040124331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13342104001991) and next prime (13342104002011).

It is not a de Polignac number, because 13342104002001 - 2¹³ = 13342103993809 is a prime.

It is a super-3 number, since 3×13342104002001³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13342104002011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223684000331 + ... + 2223684000336.

It is an arithmetic number, because the mean of its divisors is an integer number (4447368000668).

Almost surely, 2^{13342104002001} is an apocalyptic number.

It is an amenable number.

13342104002001 is a deficient number, since it is larger than the sum of its proper divisors (4447368000671).

13342104002001 is an equidigital number, since it uses as much as digits as its factorization.

13342104002001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4447368000670.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13342104002001 its reverse (10020040124331), we get a palindrome (23362144126332).

The spelling of 13342104002001 in words is "thirteen trillion, three hundred forty-two billion, one hundred four million, two thousand, one".