Base | Representation |
---|---|
bin | 10011011010100101001… |
… | …111001000111101010011 |
3 | 11201112211112101202010012 |
4 | 103122211033020331103 |
5 | 133324431242240001 |
6 | 2500532323025135 |
7 | 165252006325343 |
oct | 23324517107523 |
9 | 4645745352105 |
10 | 1334212071251 |
11 | 474921a27744 |
12 | 1966b4b0b1ab |
13 | 98a7b003797 |
14 | 4880d18cd23 |
15 | 24a8c7152bb |
hex | 136a53c8f53 |
1334212071251 has 2 divisors, whose sum is σ = 1334212071252. Its totient is φ = 1334212071250.
The previous prime is 1334212071239. The next prime is 1334212071253. The reversal of 1334212071251 is 1521702124331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1334212071251 - 210 = 1334212070227 is a prime.
Together with 1334212071253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1334212071253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667106035625 + 667106035626.
It is an arithmetic number, because the mean of its divisors is an integer number (667106035626).
Almost surely, 21334212071251 is an apocalyptic number.
1334212071251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334212071251 is an equidigital number, since it uses as much as digits as its factorization.
1334212071251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 1334212071251 its reverse (1521702124331), we get a palindrome (2855914195582).
The spelling of 1334212071251 in words is "one trillion, three hundred thirty-four billion, two hundred twelve million, seventy-one thousand, two hundred fifty-one".
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