Base | Representation |
---|---|
bin | 1100001000100111010011… |
… | …1010110101010100000101 |
3 | 1202020111100222110100210211 |
4 | 3002021310322311110011 |
5 | 3222044140240014112 |
6 | 44213142341515421 |
7 | 2544636263543536 |
oct | 302116472652405 |
9 | 52214328410724 |
10 | 13342130001157 |
11 | 4284402614471 |
12 | 15b5964412b71 |
13 | 75a207c2ca99 |
14 | 341a9659068d |
15 | 1820d581e0a7 |
hex | c2274eb5505 |
13342130001157 has 2 divisors, whose sum is σ = 13342130001158. Its totient is φ = 13342130001156.
The previous prime is 13342130001103. The next prime is 13342130001257. The reversal of 13342130001157 is 75110003124331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12272872666756 + 1069257334401 = 3503266^2 + 1034049^2 .
It is a cyclic number.
It is not a de Polignac number, because 13342130001157 - 235 = 13307770262789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13342130001257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671065000578 + 6671065000579.
It is an arithmetic number, because the mean of its divisors is an integer number (6671065000579).
Almost surely, 213342130001157 is an apocalyptic number.
It is an amenable number.
13342130001157 is a deficient number, since it is larger than the sum of its proper divisors (1).
13342130001157 is an equidigital number, since it uses as much as digits as its factorization.
13342130001157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 13342130001157 its reverse (75110003124331), we get a palindrome (88452133125488).
The spelling of 13342130001157 in words is "thirteen trillion, three hundred forty-two billion, one hundred thirty million, one thousand, one hundred fifty-seven".
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