Base | Representation |
---|---|
bin | 11000110110100001… |
… | …01010010101011111 |
3 | 1021102211210202021112 |
4 | 30123100222111133 |
5 | 204311104120211 |
6 | 10043534452235 |
7 | 651430201652 |
oct | 143320522537 |
9 | 37384722245 |
10 | 13342254431 |
11 | 572739a260 |
12 | 270436407b |
13 | 134827550c |
14 | 907dbb899 |
15 | 53150a88b |
hex | 31b42a55f |
13342254431 has 16 divisors (see below), whose sum is σ = 15066203040. Its totient is φ = 11703982080.
The previous prime is 13342254421. The next prime is 13342254433. The reversal of 13342254431 is 13445224331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13342254431 is a prime.
It is a super-2 number, since 2×133422544312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13342254433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 555095 + ... + 578631.
It is an arithmetic number, because the mean of its divisors is an integer number (941637690).
Almost surely, 213342254431 is an apocalyptic number.
13342254431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13342254431 is a deficient number, since it is larger than the sum of its proper divisors (1723948609).
13342254431 is a wasteful number, since it uses less digits than its factorization.
13342254431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25354.
The product of its digits is 34560, while the sum is 32.
Adding to 13342254431 its reverse (13445224331), we get a palindrome (26787478762).
The spelling of 13342254431 in words is "thirteen billion, three hundred forty-two million, two hundred fifty-four thousand, four hundred thirty-one".
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