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13342254431 = 1129177723537
BaseRepresentation
bin11000110110100001…
…01010010101011111
31021102211210202021112
430123100222111133
5204311104120211
610043534452235
7651430201652
oct143320522537
937384722245
1013342254431
11572739a260
12270436407b
13134827550c
14907dbb899
1553150a88b
hex31b42a55f

13342254431 has 16 divisors (see below), whose sum is σ = 15066203040. Its totient is φ = 11703982080.

The previous prime is 13342254421. The next prime is 13342254433. The reversal of 13342254431 is 13445224331.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13342254431 is a prime.

It is a super-2 number, since 2×133422544312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13342254433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 555095 + ... + 578631.

It is an arithmetic number, because the mean of its divisors is an integer number (941637690).

Almost surely, 213342254431 is an apocalyptic number.

13342254431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13342254431 is a deficient number, since it is larger than the sum of its proper divisors (1723948609).

13342254431 is a wasteful number, since it uses less digits than its factorization.

13342254431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25354.

The product of its digits is 34560, while the sum is 32.

Adding to 13342254431 its reverse (13445224331), we get a palindrome (26787478762).

The spelling of 13342254431 in words is "thirteen billion, three hundred forty-two million, two hundred fifty-four thousand, four hundred thirty-one".

Divisors: 1 11 29 319 1777 19547 23537 51533 258907 566863 682573 7508303 41825249 460077739 1212932221 13342254431