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13342300324361 is a prime number
BaseRepresentation
bin1100001000100111111100…
…0100100100001000001001
31202020111210211221200022122
43002021333010210020021
53222100012340334421
644213211304301025
72544643432346621
oct302117704441011
952214724850278
1013342300324361
11428448a777848
1215b59b1471775
1375a2342c6248
14341ab1049881
151820e57652ab
hexc227f124209

13342300324361 has 2 divisors, whose sum is σ = 13342300324362. Its totient is φ = 13342300324360.

The previous prime is 13342300324291. The next prime is 13342300324391. The reversal of 13342300324361 is 16342300324331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8944471914361 + 4397828410000 = 2990731^2 + 2097100^2 .

It is a cyclic number.

It is not a de Polignac number, because 13342300324361 - 210 = 13342300323337 is a prime.

It is not a weakly prime, because it can be changed into another prime (13342300324391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671150162180 + 6671150162181.

It is an arithmetic number, because the mean of its divisors is an integer number (6671150162181).

Almost surely, 213342300324361 is an apocalyptic number.

It is an amenable number.

13342300324361 is a deficient number, since it is larger than the sum of its proper divisors (1).

13342300324361 is an equidigital number, since it uses as much as digits as its factorization.

13342300324361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 13342300324361 its reverse (16342300324331), we get a palindrome (29684600648692).

The spelling of 13342300324361 in words is "thirteen trillion, three hundred forty-two billion, three hundred million, three hundred twenty-four thousand, three hundred sixty-one".