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13342420110434 = 26671210055217
BaseRepresentation
bin1100001000101000011000…
…1101100000110001100010
31202020112010012100102220212
43002022012031200301202
53222100234022013214
644213231223534122
72544646415460302
oct302120615406142
952215105312825
1013342420110434
1142845413528a8
1215b5a255ba342
1375a25307698c
14341ac2d0b602
1518210102753e
hexc2286360c62

13342420110434 has 4 divisors (see below), whose sum is σ = 20013630165654. Its totient is φ = 6671210055216.

The previous prime is 13342420110403. The next prime is 13342420110449. The reversal of 13342420110434 is 43401102424331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11377783371409 + 1964636739025 = 3373097^2 + 1401655^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13342420110434.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335605027607 + ... + 3335605027610.

Almost surely, 213342420110434 is an apocalyptic number.

13342420110434 is a deficient number, since it is larger than the sum of its proper divisors (6671210055220).

13342420110434 is an equidigital number, since it uses as much as digits as its factorization.

13342420110434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6671210055219.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13342420110434 its reverse (43401102424331), we get a palindrome (56743522534765).

The spelling of 13342420110434 in words is "thirteen trillion, three hundred forty-two billion, four hundred twenty million, one hundred ten thousand, four hundred thirty-four".

Divisors: 1 2 6671210055217 13342420110434