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1334244442039 is a prime number
BaseRepresentation
bin10011011010100111001…
…010100111111110110111
311201112220210022100111021
4103122213022213332313
5133330013034121124
62500535440522011
7165252551426665
oct23324712477667
94645823270437
101334244442039
11474939227363
12196703920307
1398a849288b2
14488135b7c35
1524a904ab7e4
hex136a72a7fb7

1334244442039 has 2 divisors, whose sum is σ = 1334244442040. Its totient is φ = 1334244442038.

The previous prime is 1334244441967. The next prime is 1334244442049. The reversal of 1334244442039 is 9302444424331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1334244442039 - 235 = 1299884703671 is a prime.

It is a super-2 number, since 2×13342444420392 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1334244441986 and 1334244442004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1334244442049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667122221019 + 667122221020.

It is an arithmetic number, because the mean of its divisors is an integer number (667122221020).

Almost surely, 21334244442039 is an apocalyptic number.

1334244442039 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334244442039 is an equidigital number, since it uses as much as digits as its factorization.

1334244442039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 995328, while the sum is 43.

The spelling of 1334244442039 in words is "one trillion, three hundred thirty-four billion, two hundred forty-four million, four hundred forty-two thousand, thirty-nine".