Base | Representation |
---|---|
bin | 1100001000101000110001… |
… | …1001110111101110000100 |
3 | 1202020112101102212021001111 |
4 | 3002022030121313232010 |
5 | 3222100442121412234 |
6 | 44213245414534404 |
7 | 2544652116566443 |
oct | 302121431675604 |
9 | 52215342767044 |
10 | 13342524013444 |
11 | 4284594a6a75a |
12 | 15b5a54367404 |
13 | 75a26b755b52 |
14 | 341ad2a36d5a |
15 | 18210a1ed664 |
hex | c228c677b84 |
13342524013444 has 24 divisors (see below), whose sum is σ = 24750784759680. Its totient is φ = 6271756070016.
The previous prime is 13342524013391. The next prime is 13342524013471. The reversal of 13342524013444 is 44431042524331.
It is a super-2 number, since 2×133425240134442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13342524013397 and 13342524013406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110544864 + ... + 110665495.
It is an arithmetic number, because the mean of its divisors is an integer number (1031282698320).
Almost surely, 213342524013444 is an apocalyptic number.
It is an amenable number.
13342524013444 is a deficient number, since it is larger than the sum of its proper divisors (11408260746236).
13342524013444 is a wasteful number, since it uses less digits than its factorization.
13342524013444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221211267 (or 221211265 counting only the distinct ones).
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 13342524013444 its reverse (44431042524331), we get a palindrome (57773566537775).
The spelling of 13342524013444 in words is "thirteen trillion, three hundred forty-two billion, five hundred twenty-four million, thirteen thousand, four hundred forty-four".
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