13342555040335 has 16 divisors (see below), whose sum is σ = 16903764914400. Its totient is φ = 10082245533696.

The previous prime is 13342555040303. The next prime is 13342555040341. The reversal of 13342555040335 is 53304055524331.

It is a cyclic number.

It is not a de Polignac number, because 13342555040335 - 2⁵ = 13342555040303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13342555040291 and 13342555040300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 208347730 + ... + 208411759.

It is an arithmetic number, because the mean of its divisors is an integer number (1056485307150).

Almost surely, 2^{13342555040335} is an apocalyptic number.

13342555040335 is a deficient number, since it is larger than the sum of its proper divisors (3561209874065).

13342555040335 is a wasteful number, since it uses less digits than its factorization.

13342555040335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 416759850.

The product of its (nonzero) digits is 1620000, while the sum is 43.

The spelling of 13342555040335 in words is "thirteen trillion, three hundred forty-two billion, five hundred fifty-five million, forty thousand, three hundred thirty-five".