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13343014117 is a prime number
BaseRepresentation
bin11000110110100111…
…00011110011100101
31021102220020100101001
430123103203303211
5204311302422432
610044003033301
7651436514536
oct143323436345
937386210331
1013343014117
115727868aa4
12270466b831
131348480234
1490813868d
1553160a9e7
hex31b4e3ce5

13343014117 has 2 divisors, whose sum is σ = 13343014118. Its totient is φ = 13343014116.

The previous prime is 13343014109. The next prime is 13343014133. The reversal of 13343014117 is 71141034331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8352863236 + 4990150881 = 91394^2 + 70641^2 .

It is an emirp because it is prime and its reverse (71141034331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13343014117 - 23 = 13343014109 is a prime.

It is a super-2 number, since 2×133430141172 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13343014177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671507058 + 6671507059.

It is an arithmetic number, because the mean of its divisors is an integer number (6671507059).

Almost surely, 213343014117 is an apocalyptic number.

It is an amenable number.

13343014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13343014117 is an equidigital number, since it uses as much as digits as its factorization.

13343014117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 13343014117 its reverse (71141034331), we get a palindrome (84484048448).

The spelling of 13343014117 in words is "thirteen billion, three hundred forty-three million, fourteen thousand, one hundred seventeen".