Base | Representation |
---|---|
bin | 100111110000111… |
… | …1101001011111001 |
3 | 10102222201112110121 |
4 | 1033201331023321 |
5 | 10213040121213 |
6 | 340222413241 |
7 | 45031242433 |
oct | 11741751371 |
9 | 3388645417 |
10 | 1334301433 |
11 | 6251a6463 |
12 | 312a31221 |
13 | 183587a9a |
14 | c92cd653 |
15 | 7c21888d |
hex | 4f87d2f9 |
1334301433 has 2 divisors, whose sum is σ = 1334301434. Its totient is φ = 1334301432.
The previous prime is 1334301427. The next prime is 1334301487. The reversal of 1334301433 is 3341034331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1227241024 + 107060409 = 35032^2 + 10347^2 .
It is a cyclic number.
It is not a de Polignac number, because 1334301433 - 29 = 1334300921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1334301398 and 1334301407.
It is not a weakly prime, because it can be changed into another prime (1334301413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667150716 + 667150717.
It is an arithmetic number, because the mean of its divisors is an integer number (667150717).
Almost surely, 21334301433 is an apocalyptic number.
It is an amenable number.
1334301433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334301433 is an equidigital number, since it uses as much as digits as its factorization.
1334301433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
The square root of 1334301433 is about 36528.0910122607. The cubic root of 1334301433 is about 1100.9087347420.
Adding to 1334301433 its reverse (3341034331), we get a palindrome (4675335764).
The spelling of 1334301433 in words is "one billion, three hundred thirty-four million, three hundred one thousand, four hundred thirty-three".
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