133430143442233 has 4 divisors (see below), whose sum is σ = 145560156482448. Its totient is φ = 121300130402020.

The previous prime is 133430143442209. The next prime is 133430143442237. The reversal of 133430143442233 is 332244341034331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133430143442233 - 2⁴¹ = 131231120186681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133430143442237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6065006520091 + ... + 6065006520112.

It is an arithmetic number, because the mean of its divisors is an integer number (36390039120612).

Almost surely, 2^{133430143442233} is an apocalyptic number.

It is an amenable number.

133430143442233 is a deficient number, since it is larger than the sum of its proper divisors (12130013040215).

133430143442233 is a wasteful number, since it uses less digits than its factorization.

133430143442233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12130013040214.

The product of its (nonzero) digits is 746496, while the sum is 40.

Adding to 133430143442233 its reverse (332244341034331), we get a palindrome (465674484476564).

The spelling of 133430143442233 in words is "one hundred thirty-three trillion, four hundred thirty billion, one hundred forty-three million, four hundred forty-two thousand, two hundred thirty-three".