Base | Representation |
---|---|
bin | 11110010101101011010011… |
… | …011010101010100100001111 |
3 | 122111102212201212200220201121 |
4 | 132111223103122222210033 |
5 | 114442113142224001312 |
6 | 1151441204452421411 |
7 | 40051033410053431 |
oct | 3625532332524417 |
9 | 574385655626647 |
10 | 133431001000207 |
11 | 39573851586629 |
12 | 12b6b9a4317867 |
13 | 595b6492b5a11 |
14 | 24d41485d0651 |
15 | 1065ca713c707 |
hex | 795ad36aa90f |
133431001000207 has 2 divisors, whose sum is σ = 133431001000208. Its totient is φ = 133431001000206.
The previous prime is 133431001000139. The next prime is 133431001000247. The reversal of 133431001000207 is 702000100134331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133431001000207 - 27 = 133431001000079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133431001000247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66715500500103 + 66715500500104.
It is an arithmetic number, because the mean of its divisors is an integer number (66715500500104).
Almost surely, 2133431001000207 is an apocalyptic number.
133431001000207 is a deficient number, since it is larger than the sum of its proper divisors (1).
133431001000207 is an equidigital number, since it uses as much as digits as its factorization.
133431001000207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 133431001000207 its reverse (702000100134331), we get a palindrome (835431101134538).
The spelling of 133431001000207 in words is "one hundred thirty-three trillion, four hundred thirty-one billion, one million, two hundred seven", and thus it is an aban number.
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