Base | Representation |
---|---|
bin | 1100001000101011101111… |
… | …1110110111100001010111 |
3 | 1202020121110001212102120011 |
4 | 3002022323332313201113 |
5 | 3222104110443203421 |
6 | 44213500531421051 |
7 | 2545010651452012 |
oct | 302127376674127 |
9 | 52217401772504 |
10 | 13343322241111 |
11 | 42849645aaa45 |
12 | 15b6037754787 |
13 | 75a367c38105 |
14 | 341b6aa60379 |
15 | 1821553254e1 |
hex | c22bbfb7857 |
13343322241111 has 2 divisors, whose sum is σ = 13343322241112. Its totient is φ = 13343322241110.
The previous prime is 13343322241027. The next prime is 13343322241177. The reversal of 13343322241111 is 11114222334331.
It is a strong prime.
It is an emirp because it is prime and its reverse (11114222334331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13343322241111 - 217 = 13343322110039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13343322241511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671661120555 + 6671661120556.
It is an arithmetic number, because the mean of its divisors is an integer number (6671661120556).
Almost surely, 213343322241111 is an apocalyptic number.
13343322241111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343322241111 is an equidigital number, since it uses as much as digits as its factorization.
13343322241111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 31.
Adding to 13343322241111 its reverse (11114222334331), we get a palindrome (24457544575442).
The spelling of 13343322241111 in words is "thirteen trillion, three hundred forty-three billion, three hundred twenty-two million, two hundred forty-one thousand, one hundred eleven".
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