133433334331 has 4 divisors (see below), whose sum is σ = 145563637464. Its totient is φ = 121303031200.

The previous prime is 133433334313. The next prime is 133433334341.

133433334331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133433334331 - 2⁵ = 133433334299 is a prime.

It is a super-2 number, since 2×133433334331² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133433334341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6065151550 + ... + 6065151571.

It is an arithmetic number, because the mean of its divisors is an integer number (36390909366).

Almost surely, 2^133433334331 is an apocalyptic number.

133433334331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

133433334331 is a deficient number, since it is larger than the sum of its proper divisors (12130303133).

133433334331 is a wasteful number, since it uses less digits than its factorization.

133433334331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12130303132.

The product of its digits is 104976, while the sum is 34.

It can be divided in two parts, 133433 and 334331, that added together give a palindrome (467764).

The spelling of 133433334331 in words is "one hundred thirty-three billion, four hundred thirty-three million, three hundred thirty-four thousand, three hundred thirty-one".