Base | Representation |
---|---|
bin | 111110001000101001… |
… | …1011101111010010101 |
3 | 110202102021011212102221 |
4 | 1330101103131322111 |
5 | 4141233140131401 |
6 | 141144320102341 |
7 | 12432424565632 |
oct | 1742123357225 |
9 | 422367155387 |
10 | 133434302101 |
11 | 51653204131 |
12 | 21a3aa649b1 |
13 | c77654a859 |
14 | 665b645189 |
15 | 370e5e47a1 |
hex | 1f114dde95 |
133434302101 has 2 divisors, whose sum is σ = 133434302102. Its totient is φ = 133434302100.
The previous prime is 133434302059. The next prime is 133434302107. The reversal of 133434302101 is 101203434331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131933127076 + 1501175025 = 363226^2 + 38745^2 .
It is an emirp because it is prime and its reverse (101203434331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133434302101 - 235 = 99074563733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133434302107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66717151050 + 66717151051.
It is an arithmetic number, because the mean of its divisors is an integer number (66717151051).
Almost surely, 2133434302101 is an apocalyptic number.
It is an amenable number.
133434302101 is a deficient number, since it is larger than the sum of its proper divisors (1).
133434302101 is an equidigital number, since it uses as much as digits as its factorization.
133434302101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 133434302101 its reverse (101203434331), we get a palindrome (234637736432).
The spelling of 133434302101 in words is "one hundred thirty-three billion, four hundred thirty-four million, three hundred two thousand, one hundred one".
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