Base | Representation |
---|---|
bin | 1100001000101110011011… |
… | …1000111100110100110111 |
3 | 1202020200022020102120101121 |
4 | 3002023212320330310313 |
5 | 3222112044240012023 |
6 | 44214100205004411 |
7 | 2545034542315624 |
oct | 302134670746467 |
9 | 52220266376347 |
10 | 13344042110263 |
11 | 42851a3990327 |
12 | 15b61b8853707 |
13 | 75a4511131a7 |
14 | 341bd84cb34b |
15 | 18219861ed5d |
hex | c22e6e3cd37 |
13344042110263 has 2 divisors, whose sum is σ = 13344042110264. Its totient is φ = 13344042110262.
The previous prime is 13344042110249. The next prime is 13344042110317. The reversal of 13344042110263 is 36201124044331.
It is a weak prime.
It is an emirp because it is prime and its reverse (36201124044331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13344042110263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13344042110963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6672021055131 + 6672021055132.
It is an arithmetic number, because the mean of its divisors is an integer number (6672021055132).
Almost surely, 213344042110263 is an apocalyptic number.
13344042110263 is a deficient number, since it is larger than the sum of its proper divisors (1).
13344042110263 is an equidigital number, since it uses as much as digits as its factorization.
13344042110263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 13344042110263 its reverse (36201124044331), we get a palindrome (49545166154594).
The spelling of 13344042110263 in words is "thirteen trillion, three hundred forty-four billion, forty-two million, one hundred ten thousand, two hundred sixty-three".
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