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1334412304663 = 1619824220077
BaseRepresentation
bin10011011010110001001…
…010111110000100010111
311201120100111011122201111
4103122301022332010113
5133330334022222123
62501004234435451
7165256660304254
oct23326112760427
94646314148644
101334412304663
11474a14a59aa9
1219674bb92b87
1398ab06400a9
144882b9d242b
1524aa00b890d
hex136b12be117

1334412304663 has 4 divisors (see below), whose sum is σ = 1335236526360. Its totient is φ = 1333588082968.

The previous prime is 1334412304649. The next prime is 1334412304669. The reversal of 1334412304663 is 3664032144331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1334412304663 - 29 = 1334412304151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334412304669) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412108420 + ... + 412111657.

It is an arithmetic number, because the mean of its divisors is an integer number (333809131590).

Almost surely, 21334412304663 is an apocalyptic number.

1334412304663 is a deficient number, since it is larger than the sum of its proper divisors (824221697).

1334412304663 is an equidigital number, since it uses as much as digits as its factorization.

1334412304663 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 824221696.

The product of its (nonzero) digits is 373248, while the sum is 40.

Adding to 1334412304663 its reverse (3664032144331), we get a palindrome (4998444448994).

The spelling of 1334412304663 in words is "one trillion, three hundred thirty-four billion, four hundred twelve million, three hundred four thousand, six hundred sixty-three".

Divisors: 1 1619 824220077 1334412304663