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133442104355023 = 1306811021128583
BaseRepresentation
bin11110010101110101101001…
…001110100110100011001111
3122111110221101200121210010011
4132111311221032212203033
5114442303412203330043
61151450242332054051
740051605513033322
oct3625655116464317
9574427350553104
10133442104355023
113957852a097422
1212b71b82904327
13595c6c8759b59
1424d48bd0c67b9
151066206ce559d
hex795d693a68cf

133442104355023 has 4 divisors (see below), whose sum is σ = 133443125614288. Its totient is φ = 133441083095760.

The previous prime is 133442104354973. The next prime is 133442104355029. The reversal of 133442104355023 is 320553401244331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133442104355023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133442104355029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510433611 + ... + 510694972.

It is an arithmetic number, because the mean of its divisors is an integer number (33360781403572).

Almost surely, 2133442104355023 is an apocalyptic number.

133442104355023 is a deficient number, since it is larger than the sum of its proper divisors (1021259265).

133442104355023 is a wasteful number, since it uses less digits than its factorization.

133442104355023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1021259264.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 133442104355023 its reverse (320553401244331), we get a palindrome (453995505599354).

The spelling of 133442104355023 in words is "one hundred thirty-three trillion, four hundred forty-two billion, one hundred four million, three hundred fifty-five thousand, twenty-three".

Divisors: 1 130681 1021128583 133442104355023