13344212041 has 4 divisors (see below), whose sum is σ = 13348084500. Its totient is φ = 13340339584.

The previous prime is 13344212009. The next prime is 13344212051. The reversal of 13344212041 is 14021244331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14021244331 = 59 ⋅237648209.

It can be written as a sum of positive squares in 2 ways, for example, as 3693114441 + 9651097600 = 60771^2 + 98240^2 .

It is a cyclic number.

It is not a de Polignac number, because 13344212041 - 2⁵ = 13344212009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13344211997 and 13344212015.

It is not an unprimeable number, because it can be changed into a prime (13344212051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1931056 + ... + 1937953.

It is an arithmetic number, because the mean of its divisors is an integer number (3337021125).

Almost surely, 2^13344212041 is an apocalyptic number.

It is an amenable number.

13344212041 is a deficient number, since it is larger than the sum of its proper divisors (3872459).

13344212041 is an equidigital number, since it uses as much as digits as its factorization.

13344212041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3872458.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13344212041 its reverse (14021244331), we get a palindrome (27365456372).

The spelling of 13344212041 in words is "thirteen billion, three hundred forty-four million, two hundred twelve thousand, forty-one".