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1334432200442 = 21160656009111
BaseRepresentation
bin10011011010110010010…
…110110111011011111010
311201120101212121110121012
4103122302112313123322
5133330404120403232
62501010225113522
7165260321360405
oct23326226673372
94646355543535
101334432200442
11474a25208aa0
121967567888a2
1398ab47b7c43
14488304d0d3c
1524aa1be89b2
hex136b25b76fa

1334432200442 has 8 divisors (see below), whose sum is σ = 2183616328032. Its totient is φ = 606560091100.

The previous prime is 1334432200397. The next prime is 1334432200487. The reversal of 1334432200442 is 2440022344331.

It is an interprime number because it is at equal distance from previous prime (1334432200397) and next prime (1334432200487).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1334432200399 and 1334432200408.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30328004534 + ... + 30328004577.

It is an arithmetic number, because the mean of its divisors is an integer number (272952041004).

Almost surely, 21334432200442 is an apocalyptic number.

1334432200442 is a deficient number, since it is larger than the sum of its proper divisors (849184127590).

1334432200442 is a wasteful number, since it uses less digits than its factorization.

1334432200442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60656009124.

The product of its (nonzero) digits is 55296, while the sum is 32.

Adding to 1334432200442 its reverse (2440022344331), we get a palindrome (3774454544773).

The spelling of 1334432200442 in words is "one trillion, three hundred thirty-four billion, four hundred thirty-two million, two hundred thousand, four hundred forty-two".

Divisors: 1 2 11 22 60656009111 121312018222 667216100221 1334432200442