Base | Representation |
---|---|
bin | 111110001001001001… |
… | …1101111110100110101 |
3 | 110202110102212222002221 |
4 | 1330102103233310311 |
5 | 4141301443341233 |
6 | 141150121202341 |
7 | 12433021040005 |
oct | 1742223576465 |
9 | 422412788087 |
10 | 133451152693 |
11 | 51661773241 |
12 | 21a446303b1 |
13 | c779b9a611 |
14 | 665d990005 |
15 | 3710d2242d |
hex | 1f124efd35 |
133451152693 has 2 divisors, whose sum is σ = 133451152694. Its totient is φ = 133451152692.
The previous prime is 133451152657. The next prime is 133451152711. The reversal of 133451152693 is 396251154331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95668345809 + 37782806884 = 309303^2 + 194378^2 .
It is a cyclic number.
It is not a de Polignac number, because 133451152693 - 217 = 133451021621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133451152193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66725576346 + 66725576347.
It is an arithmetic number, because the mean of its divisors is an integer number (66725576347).
Almost surely, 2133451152693 is an apocalyptic number.
It is an amenable number.
133451152693 is a deficient number, since it is larger than the sum of its proper divisors (1).
133451152693 is an equidigital number, since it uses as much as digits as its factorization.
133451152693 is an evil number, because the sum of its binary digits is even.
The product of its digits is 291600, while the sum is 43.
The spelling of 133451152693 in words is "one hundred thirty-three billion, four hundred fifty-one million, one hundred fifty-two thousand, six hundred ninety-three".
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