Base | Representation |
---|---|
bin | 11110010110000010111101… |
… | …011001010101011010100010 |
3 | 122111112022022001221201001112 |
4 | 132112002331121111122202 |
5 | 114443022202221401300 |
6 | 1151501005134303322 |
7 | 40052623015402244 |
oct | 3626027531253242 |
9 | 574468261851045 |
10 | 133456401356450 |
11 | 395835a6401187 |
12 | 12b748b2957b42 |
13 | 5960b66756a03 |
14 | 24d5477bd2094 |
15 | 1066792043e35 |
hex | 7960bd6556a2 |
133456401356450 has 24 divisors (see below), whose sum is σ = 248229256151568. Its totient is φ = 53382485353680.
The previous prime is 133456401356441. The next prime is 133456401356497. The reversal of 133456401356450 is 54653104654331.
It is a super-2 number, since 2×1334564013564502 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (50).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 46099469 + ... + 48908831.
It is an arithmetic number, because the mean of its divisors is an integer number (10342885672982).
Almost surely, 2133456401356450 is an apocalyptic number.
133456401356450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133456401356450 is a deficient number, since it is larger than the sum of its proper divisors (114772854795118).
133456401356450 is a wasteful number, since it uses less digits than its factorization.
133456401356450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3759458 (or 3759453 counting only the distinct ones).
The product of its (nonzero) digits is 7776000, while the sum is 50.
The spelling of 133456401356450 in words is "one hundred thirty-three trillion, four hundred fifty-six billion, four hundred one million, three hundred fifty-six thousand, four hundred fifty".
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