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133456414441159 is a prime number
BaseRepresentation
bin11110010110000010111110…
…001011001111111011000111
3122111112022022222120110220101
4132112002332023033323013
5114443022214044104114
61151501010322544531
740052623234540135
oct3626027613177307
9574468288513811
10133456414441159
1139583602828997
1212b748b7208147
135960b69388644
1424d547983a755
15106679327ad74
hex7960be2cfec7

133456414441159 has 2 divisors, whose sum is σ = 133456414441160. Its totient is φ = 133456414441158.

The previous prime is 133456414441111. The next prime is 133456414441213. The reversal of 133456414441159 is 951144414654331.

It is a weak prime.

It is an emirp because it is prime and its reverse (951144414654331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133456414441159 - 235 = 133422054702791 is a prime.

It is a super-2 number, since 2×1334564144411592 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133456414441759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66728207220579 + 66728207220580.

It is an arithmetic number, because the mean of its divisors is an integer number (66728207220580).

Almost surely, 2133456414441159 is an apocalyptic number.

133456414441159 is a deficient number, since it is larger than the sum of its proper divisors (1).

133456414441159 is an equidigital number, since it uses as much as digits as its factorization.

133456414441159 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12441600, while the sum is 55.

The spelling of 133456414441159 in words is "one hundred thirty-three trillion, four hundred fifty-six billion, four hundred fourteen million, four hundred forty-one thousand, one hundred fifty-nine".