Base | Representation |
---|---|
bin | 11110010110000011000111… |
… | …000101111110100110110100 |
3 | 122111112022201102002121202110 |
4 | 132112003013011332212310 |
5 | 114443023020344220302 |
6 | 1151501033225411020 |
7 | 40052630032326402 |
oct | 3626030705764664 |
9 | 574468642077673 |
10 | 133456564054452 |
11 | 3958367a226641 |
12 | 12b74939339a70 |
13 | 5960b91380512 |
14 | 24d5491664472 |
15 | 10667a1480b6c |
hex | 7960c717e9b4 |
133456564054452 has 48 divisors (see below), whose sum is σ = 314995648262400. Its totient is φ = 43971975928320.
The previous prime is 133456564054447. The next prime is 133456564054469. The reversal of 133456564054452 is 254450465654331.
It is a junction number, because it is equal to n+sod(n) for n = 133456564054392 and 133456564054401.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16042924 + ... + 22897347.
It is an arithmetic number, because the mean of its divisors is an integer number (6562409338800).
Almost surely, 2133456564054452 is an apocalyptic number.
133456564054452 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133456564054452 is an abundant number, since it is smaller than the sum of its proper divisors (181539084207948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133456564054452 is a wasteful number, since it uses less digits than its factorization.
133456564054452 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38943576 (or 38943574 counting only the distinct ones).
The product of its (nonzero) digits is 103680000, while the sum is 57.
The spelling of 133456564054452 in words is "one hundred thirty-three trillion, four hundred fifty-six billion, five hundred sixty-four million, fifty-four thousand, four hundred fifty-two".
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