Base | Representation |
---|---|
bin | 11110010110001000011000… |
… | …010011100111010111001101 |
3 | 122111112212022200200020002121 |
4 | 132112020120103213113031 |
5 | 114443121112204113203 |
6 | 1151503410445252541 |
7 | 40053220160262523 |
oct | 3626103023472715 |
9 | 574485280606077 |
10 | 133462221551053 |
11 | 3958601279256a |
12 | 12b75a57b64151 |
13 | 59615834b9345 |
14 | 24d586ab98313 |
15 | 10669d2eb10bd |
hex | 7962184e75cd |
133462221551053 has 4 divisors (see below), whose sum is σ = 135151616760640. Its totient is φ = 131772826341468.
The previous prime is 133462221551047. The next prime is 133462221551137. The reversal of 133462221551053 is 350155122264331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133462221551053 - 213 = 133462221542861 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133462221551003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 844697604675 + ... + 844697604832.
It is an arithmetic number, because the mean of its divisors is an integer number (33787904190160).
Almost surely, 2133462221551053 is an apocalyptic number.
It is an amenable number.
133462221551053 is a deficient number, since it is larger than the sum of its proper divisors (1689395209587).
133462221551053 is an equidigital number, since it uses as much as digits as its factorization.
133462221551053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1689395209586.
The product of its (nonzero) digits is 648000, while the sum is 43.
The spelling of 133462221551053 in words is "one hundred thirty-three trillion, four hundred sixty-two billion, two hundred twenty-one million, five hundred fifty-one thousand, fifty-three".
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