Base | Representation |
---|---|
bin | 11110010110001010111110… |
… | …101101010101011110000100 |
3 | 122111120010112020212100021122 |
4 | 132112022332231111132010 |
5 | 114443142321401430424 |
6 | 1151504551454333112 |
7 | 40053346306662440 |
oct | 3626127655253604 |
9 | 574503466770248 |
10 | 133465013311364 |
11 | 39587215652399 |
12 | 12b764b6aba198 |
13 | 59619099c0017 |
14 | 24d5a53875820 |
15 | 1066ae811e45e |
hex | 7962beb55784 |
133465013311364 has 48 divisors (see below), whose sum is σ = 275546325282816. Its totient is φ = 55353017412000.
The previous prime is 133465013311187. The next prime is 133465013311397. The reversal of 133465013311364 is 463113310564331.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41433539 + ... + 44538389.
It is an arithmetic number, because the mean of its divisors is an integer number (5740548443392).
Almost surely, 2133465013311364 is an apocalyptic number.
133465013311364 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
133465013311364 is an abundant number, since it is smaller than the sum of its proper divisors (142081311971452).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133465013311364 is a wasteful number, since it uses less digits than its factorization.
133465013311364 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3154416 (or 3154414 counting only the distinct ones).
The product of its (nonzero) digits is 699840, while the sum is 44.
Adding to 133465013311364 its reverse (463113310564331), we get a palindrome (596578323875695).
The spelling of 133465013311364 in words is "one hundred thirty-three trillion, four hundred sixty-five billion, thirteen million, three hundred eleven thousand, three hundred sixty-four".
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