Base | Representation |
---|---|
bin | 11000110111000101… |
… | …10101110100001100 |
3 | 1021110011202212110201 |
4 | 30123202311310030 |
5 | 204313314120134 |
6 | 10044224543244 |
7 | 651515540611 |
oct | 143342656414 |
9 | 37404685421 |
10 | 13347020044 |
11 | 572a054786 |
12 | 2705a81b24 |
13 | 13492536c7 |
14 | 90889c508 |
15 | 531b4c914 |
hex | 31b8b5d0c |
13347020044 has 12 divisors (see below), whose sum is σ = 23405250064. Its totient is φ = 6659805744.
The previous prime is 13347020039. The next prime is 13347020069. The reversal of 13347020044 is 44002074331.
13347020044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13347019994 and 13347020021.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3423879 + ... + 3427774.
Almost surely, 213347020044 is an apocalyptic number.
It is an amenable number.
13347020044 is a deficient number, since it is larger than the sum of its proper divisors (10058230020).
13347020044 is a wasteful number, since it uses less digits than its factorization.
13347020044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6852144 (or 6852142 counting only the distinct ones).
The product of its (nonzero) digits is 8064, while the sum is 28.
Adding to 13347020044 its reverse (44002074331), we get a palindrome (57349094375).
The spelling of 13347020044 in words is "thirteen billion, three hundred forty-seven million, twenty thousand, forty-four".
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