Base | Representation |
---|---|
bin | 10011011011000100000… |
… | …000100000110101100101 |
3 | 11201121011111211102210201 |
4 | 103123010000200311211 |
5 | 133332010423034342 |
6 | 2501055444150501 |
7 | 165300545421544 |
oct | 23330400406545 |
9 | 4647144742721 |
10 | 1334728330597 |
11 | 475067389a62 |
12 | 196819998431 |
13 | 98b30c5c49c |
14 | 4885b97815b |
15 | 24abcbe0db7 |
hex | 136c4020d65 |
1334728330597 has 2 divisors, whose sum is σ = 1334728330598. Its totient is φ = 1334728330596.
The previous prime is 1334728330567. The next prime is 1334728330601. The reversal of 1334728330597 is 7950338274331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 672521365476 + 662206965121 = 820074^2 + 813761^2 .
It is an emirp because it is prime and its reverse (7950338274331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1334728330597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334728330567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667364165298 + 667364165299.
It is an arithmetic number, because the mean of its divisors is an integer number (667364165299).
Almost surely, 21334728330597 is an apocalyptic number.
It is an amenable number.
1334728330597 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334728330597 is an equidigital number, since it uses as much as digits as its factorization.
1334728330597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 55.
The spelling of 1334728330597 in words is "one trillion, three hundred thirty-four billion, seven hundred twenty-eight million, three hundred thirty thousand, five hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •