13350161145203 has 4 divisors (see below), whose sum is σ = 13350276023640. Its totient is φ = 13350046266768.

The previous prime is 13350161145199. The next prime is 13350161145221. The reversal of 13350161145203 is 30254116105331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13350161145203 - 2² = 13350161145199 is a prime.

It is a super-3 number, since 3×13350161145203³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13350161145283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57264725 + ... + 57497382.

It is an arithmetic number, because the mean of its divisors is an integer number (3337569005910).

Almost surely, 2^{13350161145203} is an apocalyptic number.

13350161145203 is a deficient number, since it is larger than the sum of its proper divisors (114878437).

13350161145203 is a wasteful number, since it uses less digits than its factorization.

13350161145203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114878436.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 13350161145203 in words is "thirteen trillion, three hundred fifty billion, one hundred sixty-one million, one hundred forty-five thousand, two hundred three".