Search a number
-
+
1335044042513 is a prime number
BaseRepresentation
bin10011011011010110110…
…100110110111100010001
311201121222111220021010122
4103123112310312330101
5133333132233330023
62501151043040025
7165311431060466
oct23332664667421
94647874807118
101335044042513
11475209614aa5
121968a7670015
1398b8149b97c
144888b87b66d
1524ada7a52c8
hex136d6d36f11

1335044042513 has 2 divisors, whose sum is σ = 1335044042514. Its totient is φ = 1335044042512.

The previous prime is 1335044042419. The next prime is 1335044042569. The reversal of 1335044042513 is 3152404405331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1226297108689 + 108746933824 = 1107383^2 + 329768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1335044042513 is a prime.

It is not a weakly prime, because it can be changed into another prime (1335044042113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667522021256 + 667522021257.

It is an arithmetic number, because the mean of its divisors is an integer number (667522021257).

Almost surely, 21335044042513 is an apocalyptic number.

It is an amenable number.

1335044042513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335044042513 is an equidigital number, since it uses as much as digits as its factorization.

1335044042513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 1335044042513 its reverse (3152404405331), we get a palindrome (4487448447844).

The spelling of 1335044042513 in words is "one trillion, three hundred thirty-five billion, forty-four million, forty-two thousand, five hundred thirteen".