1335050054201 has 4 divisors (see below), whose sum is σ = 1338236331600. Its totient is φ = 1331863776804.

The previous prime is 1335050054077. The next prime is 1335050054203. The reversal of 1335050054201 is 1024500505331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1335050054201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1335050054203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1593138071 + ... + 1593138908.

It is an arithmetic number, because the mean of its divisors is an integer number (334559082900).

Almost surely, 2^{1335050054201} is an apocalyptic number.

It is an amenable number.

1335050054201 is a deficient number, since it is larger than the sum of its proper divisors (3186277399).

1335050054201 is an equidigital number, since it uses as much as digits as its factorization.

1335050054201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3186277398.

The product of its (nonzero) digits is 9000, while the sum is 29.

Adding to 1335050054201 its reverse (1024500505331), we get a palindrome (2359550559532).

The spelling of 1335050054201 in words is "one trillion, three hundred thirty-five billion, fifty million, fifty-four thousand, two hundred one".