1335065040031 has 4 divisors (see below), whose sum is σ = 1335733577352. Its totient is φ = 1334396502712.

The previous prime is 1335065039963. The next prime is 1335065040037. The reversal of 1335065040031 is 1300405605331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1335065040031 is a prime.

It is a super-2 number, since 2×1335065040031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1335065039975 and 1335065040002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1335065040037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334265665 + ... + 334269658.

It is an arithmetic number, because the mean of its divisors is an integer number (333933394338).

Almost surely, 2^{1335065040031} is an apocalyptic number.

1335065040031 is a deficient number, since it is larger than the sum of its proper divisors (668537321).

1335065040031 is an equidigital number, since it uses as much as digits as its factorization.

1335065040031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668537320.

The product of its (nonzero) digits is 16200, while the sum is 31.

The spelling of 1335065040031 in words is "one trillion, three hundred thirty-five billion, sixty-five million, forty thousand, thirty-one".