Base | Representation |
---|---|
bin | 1100001001001000101111… |
… | …1111100001110000111111 |
3 | 1202021100112121100022021121 |
4 | 3002102023333201300333 |
5 | 3222221031400323432 |
6 | 44221225223011411 |
7 | 2545404610253413 |
oct | 302221377416077 |
9 | 52240477308247 |
10 | 13351107042367 |
11 | 4288199954396 |
12 | 15b764a899b67 |
13 | 75b008a01ca3 |
14 | 3422a890ad43 |
15 | 18245d9b3197 |
hex | c248bfe1c3f |
13351107042367 has 2 divisors, whose sum is σ = 13351107042368. Its totient is φ = 13351107042366.
The previous prime is 13351107042353. The next prime is 13351107042391. The reversal of 13351107042367 is 76324070115331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13351107042367 - 223 = 13351098653759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13351107042347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675553521183 + 6675553521184.
It is an arithmetic number, because the mean of its divisors is an integer number (6675553521184).
Almost surely, 213351107042367 is an apocalyptic number.
13351107042367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351107042367 is an equidigital number, since it uses as much as digits as its factorization.
13351107042367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 317520, while the sum is 43.
Adding to 13351107042367 its reverse (76324070115331), we get a palindrome (89675177157698).
The spelling of 13351107042367 in words is "thirteen trillion, three hundred fifty-one billion, one hundred seven million, forty-two thousand, three hundred sixty-seven".
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