Base | Representation |
---|---|
bin | 11110010110110110000010… |
… | …001011000000100111011001 |
3 | 122111201112212000220022201110 |
4 | 132112312002023000213121 |
5 | 114444422011013222340 |
6 | 1151542115030410533 |
7 | 40056604022036331 |
oct | 3626660213004731 |
9 | 574645760808643 |
10 | 133511242320345 |
11 | 395a488872803a |
12 | 12b83458b00a49 |
13 | 59660964114c6 |
14 | 24d7d9b4260c1 |
15 | 1067e018c8680 |
hex | 796d822c09d9 |
133511242320345 has 16 divisors (see below), whose sum is σ = 214511786830080. Its totient is φ = 70908062865024.
The previous prime is 133511242320301. The next prime is 133511242320367. The reversal of 133511242320345 is 543023242115331.
It is a happy number.
It is not a de Polignac number, because 133511242320345 - 213 = 133511242312153 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18620811244 + ... + 18620818413.
It is an arithmetic number, because the mean of its divisors is an integer number (13406986676880).
Almost surely, 2133511242320345 is an apocalyptic number.
133511242320345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133511242320345 is a deficient number, since it is larger than the sum of its proper divisors (81000544509735).
133511242320345 is a wasteful number, since it uses less digits than its factorization.
133511242320345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37241629904.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 133511242320345 its reverse (543023242115331), we get a palindrome (676534484435676).
The spelling of 133511242320345 in words is "one hundred thirty-three trillion, five hundred eleven billion, two hundred forty-two million, three hundred twenty thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •