Base | Representation |
---|---|
bin | 1100001001001001101111… |
… | …0000110001100001011111 |
3 | 1202021101020001011202010111 |
4 | 3002102123300301201133 |
5 | 3222222102113011312 |
6 | 44221311353350451 |
7 | 2545414302121261 |
oct | 302223360614137 |
9 | 52241201152114 |
10 | 13351371610207 |
11 | 42883152280a4 |
12 | 15b7703408427 |
13 | 75b04b7753c7 |
14 | 3422d1ad9b31 |
15 | 182476d238a7 |
hex | c249bc3185f |
13351371610207 has 2 divisors, whose sum is σ = 13351371610208. Its totient is φ = 13351371610206.
The previous prime is 13351371610177. The next prime is 13351371610219. The reversal of 13351371610207 is 70201617315331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13351371610207 - 27 = 13351371610079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13351371610207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13351371610237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675685805103 + 6675685805104.
It is an arithmetic number, because the mean of its divisors is an integer number (6675685805104).
Almost surely, 213351371610207 is an apocalyptic number.
13351371610207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351371610207 is an equidigital number, since it uses as much as digits as its factorization.
13351371610207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 79380, while the sum is 40.
Adding to 13351371610207 its reverse (70201617315331), we get a palindrome (83552988925538).
The spelling of 13351371610207 in words is "thirteen trillion, three hundred fifty-one billion, three hundred seventy-one million, six hundred ten thousand, two hundred seven".
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