133514462443 has 4 divisors (see below), whose sum is σ = 133554214080. Its totient is φ = 133474710808.

The previous prime is 133514462437. The next prime is 133514462489. The reversal of 133514462443 is 344264415331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344264415331 = 16361 ⋅21041771.

It is a cyclic number.

It is not a de Polignac number, because 133514462443 - 2³³ = 124924527851 is a prime.

It is a super-2 number, since 2×133514462443² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133514462396 and 133514462405.

It is not an unprimeable number, because it can be changed into a prime (133514462243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19870780 + ... + 19877497.

It is an arithmetic number, because the mean of its divisors is an integer number (33388553520).

Almost surely, 2^133514462443 is an apocalyptic number.

133514462443 is a deficient number, since it is larger than the sum of its proper divisors (39751637).

133514462443 is an equidigital number, since it uses as much as digits as its factorization.

133514462443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39751636.

The product of its digits is 414720, while the sum is 40.

Adding to 133514462443 its reverse (344264415331), we get a palindrome (477778877774).

The spelling of 133514462443 in words is "one hundred thirty-three billion, five hundred fourteen million, four hundred sixty-two thousand, four hundred forty-three".