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133514462489 is a prime number
BaseRepresentation
bin111110001011000010…
…1010000010100011001
3110202121212000102211012
41330112011100110121
54141414200244424
6141200302143305
712434420130452
oct1742605202431
9422555012735
10133514462489
1151694484891
1221a61881b35
13c78a035c35
146668150129
15371667ab0e
hex1f16150519

133514462489 has 2 divisors, whose sum is σ = 133514462490. Its totient is φ = 133514462488.

The previous prime is 133514462437. The next prime is 133514462491. The reversal of 133514462489 is 984264415331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133455049225 + 59413264 = 365315^2 + 7708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133514462489 is a prime.

It is a super-2 number, since 2×1335144624892 (a number of 23 digits) contains 22 as substring.

Together with 133514462491, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133514462689) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66757231244 + 66757231245.

It is an arithmetic number, because the mean of its divisors is an integer number (66757231245).

Almost surely, 2133514462489 is an apocalyptic number.

It is an amenable number.

133514462489 is a deficient number, since it is larger than the sum of its proper divisors (1).

133514462489 is an equidigital number, since it uses as much as digits as its factorization.

133514462489 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2488320, while the sum is 50.

The spelling of 133514462489 in words is "one hundred thirty-three billion, five hundred fourteen million, four hundred sixty-two thousand, four hundred eighty-nine".