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13351455349873 is a prime number
BaseRepresentation
bin1100001001001010000011…
…0000001101110001110001
31202021101102212202011100121
43002102200300031301301
53222222240032143443
644221323544250241
72545416336651244
oct302224060156161
952241385664317
1013351455349873
114288358522a33
1215b7727470981
1375b062c149c4
143422dcc9725b
1518247e3654ed
hexc24a0c0dc71

13351455349873 has 2 divisors, whose sum is σ = 13351455349874. Its totient is φ = 13351455349872.

The previous prime is 13351455349849. The next prime is 13351455349879. The reversal of 13351455349873 is 37894355415331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12211830778849 + 1139624571024 = 3494543^2 + 1067532^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351455349873 - 213 = 13351455341681 is a prime.

It is a super-2 number, since 2×133514553498732 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13351455349879) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675727674936 + 6675727674937.

It is an arithmetic number, because the mean of its divisors is an integer number (6675727674937).

Almost surely, 213351455349873 is an apocalyptic number.

It is an amenable number.

13351455349873 is a deficient number, since it is larger than the sum of its proper divisors (1).

13351455349873 is an equidigital number, since it uses as much as digits as its factorization.

13351455349873 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 81648000, while the sum is 61.

The spelling of 13351455349873 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty-five million, three hundred forty-nine thousand, eight hundred seventy-three".