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13351455349949 is a prime number
BaseRepresentation
bin1100001001001010000011…
…0000001101110010111101
31202021101102212202011110102
43002102200300031302331
53222222240032144244
644221323544250445
72545416336651413
oct302224060156275
952241385664412
1013351455349949
114288358522aa2
1215b7727470a25
1375b062c14a52
143422dcc972b3
1518247e36554e
hexc24a0c0dcbd

13351455349949 has 2 divisors, whose sum is σ = 13351455349950. Its totient is φ = 13351455349948.

The previous prime is 13351455349933. The next prime is 13351455350017. The reversal of 13351455349949 is 94994355415331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13349341005625 + 2114344324 = 3653675^2 + 45982^2 .

It is a cyclic number.

It is not a de Polignac number, because 13351455349949 - 24 = 13351455349933 is a prime.

It is a super-2 number, since 2×133514553499492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13351455349919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675727674974 + 6675727674975.

It is an arithmetic number, because the mean of its divisors is an integer number (6675727674975).

Almost surely, 213351455349949 is an apocalyptic number.

It is an amenable number.

13351455349949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13351455349949 is an equidigital number, since it uses as much as digits as its factorization.

13351455349949 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 157464000, while the sum is 65.

The spelling of 13351455349949 in words is "thirteen trillion, three hundred fifty-one billion, four hundred fifty-five million, three hundred forty-nine thousand, nine hundred forty-nine".