Base | Representation |
---|---|
bin | 11000110111100111… |
… | …11011110110101111 |
3 | 1021110111012112111121 |
4 | 30123303323312233 |
5 | 204320441014411 |
6 | 10044505001411 |
7 | 651601613365 |
oct | 143363736657 |
9 | 37414175447 |
10 | 13351501231 |
11 | 5731635542 |
12 | 2707483267 |
13 | 134a1622b3 |
14 | 909307635 |
15 | 532235571 |
hex | 31bcfbdaf |
13351501231 has 2 divisors, whose sum is σ = 13351501232. Its totient is φ = 13351501230.
The previous prime is 13351501183. The next prime is 13351501243. The reversal of 13351501231 is 13210515331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13351501231 - 227 = 13217283503 is a prime.
It is a super-2 number, since 2×133515012312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13351501196 and 13351501205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13351501291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675750615 + 6675750616.
It is an arithmetic number, because the mean of its divisors is an integer number (6675750616).
Almost surely, 213351501231 is an apocalyptic number.
13351501231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351501231 is an equidigital number, since it uses as much as digits as its factorization.
13351501231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
The spelling of 13351501231 in words is "thirteen billion, three hundred fifty-one million, five hundred one thousand, two hundred thirty-one".
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